Question

How would I go about using regx to return all characters between two brackets.
Here is an example:

foobar['infoNeededHere']ddd
needs to return infoNeededHere

I found a regex to do it between curly brackets but all attempts at making it work with square brackets have failed. Here is that regex: (?<={)[^}]*(?=}) and here is my attempt to hack it

(?<=[)[^}]*(?=])

Final Solution:

import re

str = "foobar['InfoNeeded'],"
match = re.match(r"^.*\['(.*)'\].*$",str)
print match.group(1)

Answer 1

^.*\['(.*)'\].*$ will match a line and capture what you want in a group.

You have to escape the [ and ] with \

The documentation at the rubular.com proof link will explain how the expression is formed.