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Editorial Team
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Asked: 2026-05-23T07:55:17+00:00

How would i sequence the following code so one line runs after the previous

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How would i sequence the following code so one line runs after the previous ?

$('#jqNav li a').click(function(e){

    if($(this).parent().is(".nav1")){ $('.landing .main .nav ul').css({ "background-position" : "0 -50px" });} 
    else if($(this).parent().is(".nav2")) { $('.landing .main .nav ul').css({ "background-position" : "0 -100px" });}
    else if($(this).parent().is(".nav3")) { $('.landing .main .nav ul').css({ "background-position" : "0 -150px" });}
    else if($(this).parent().is(".nav4")) { $('.landing .main .nav ul').css({ "background-position" : "0 -200px" });};

    stopAnim = true;
    $page = $(this).attr('href');
    var $hashTag = $(this).attr('name');
    window.location.hash = $hashTag;
    loadData();
    $(window).scrollTop(0);
    e.preventDefault();

});
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1 Answer

  1. Editorial Team

    I would already bind the ajax call inside of the loadData block to a method on success. I have fabricated and tested (FF 5.0 & IE 9) the following code snippet and the success method is called (you need to create the ‘test.html’ file):

    <html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.5.1.min.js"></script>
<script>
$(function()
{
    $('a').click(function()
    {
        loadData();
        return false;
    });

    function loadData()
    {
        $.ajax({
          url: "test.html",
          context: document.body,
          success: loadDataSuccess()
        });
    }

    function loadDataSuccess()
    {
        alert('success!');
        $(window).scrollTop(0);
    }
});
</script>
</head>
<body>
<a href="bla.html">Test</a>
</body>
</html>

    The only thing I noticed was that ‘e.preventDefault’ would not stop me from following the link so I changed that to ‘return false’.

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