Question

How would I use a IN table with like? So that I could use % in them? By in I mean:

SELECT fields 
  FROM table 
 WHERE age = "50" 
   AND name IN ("tim", "bob", "nancy", "john");

I already tried:

SELECT fields 
  FROM table 
 WHERE age = "50" 
   AND name LIKE ("2010-09-17%", "2010-09-16%")

But it gave the error “Operand should contain 1 column(s)”

Answer 1

You can use a number of LIKE expressions:

SELECT fields 
  FROM table 
  WHERE age = "50" 
        AND (
             name LIKE "2010-09-17%" 
             OR name LIKE "2010-09-16%"
            );

or you can use a regex:

SELECT fields 
  FROM table 
 WHERE age = "50" 
       AND name REGEXP "2010-09-17.*|2010-09-16.*";

or, cleverly

SELECT fields 
  FROM table 
 WHERE age = "50" 
       AND name REGEXP "2010-09-1(6|7).*";