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Home/ Questions/Q 5974435
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T20:56:34+00:00 2026-05-22T20:56:34+00:00

How would one implement in R the function apply.func(func, arg.list) , which takes an

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How would one implement in R the function apply.func(func, arg.list), which takes an arbitrary function func and a suitable list arg.list as arguments, and returns the result of calling func with the arguments contained in arg.list. E.g.

apply.func(foo, list(x="A", y=1, z=TRUE))

is equivalent to

foo(x="A", y=1, z=TRUE)

Thanks!

P.S. FWIW, the Python equivalent of apply.func would be something like

def apply_func(func, arg_list):
    return func(*arg_list)

or

def apply_func(func, kwarg_dict):
    return func(**kwarg_dict)

or some variant thereof.

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  1. Editorial Team
    Editorial Team
    2026-05-22T20:56:35+00:00Added an answer on May 22, 2026 at 8:56 pm

    I think do.call is what you’re looking for. You can read about it via ?do.call.

    The classic example of how folks use do.call is to rbind data frames or matrices together:

    d1 <- data.frame(x = 1:5,y = letters[1:5])
    d2 <- data.frame(x = 6:10,y = letters[6:10])
    
    do.call(rbind,list(d1,d2))
    

    Here’s another fairly trivial example using sum:

    do.call(sum,list(1:5,runif(10)))
    
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