Question

$("html").ajaxError(function (event, jqXHR, ajaxSettings, thrownError){
  //show proper message based on error.
});

I’m also sending JavaScript errors to server using $.ajax() from catch block and from window.onerror function. In case those two calls fail, I don’t want it to come to above ajaxError handler.

Answer 1

The first error handler will catch all exceptions thrown by jQuery’s ajax functions. If you don’t want it to handle an exception, I would suggest inspecting the URL of the ajax request to see if it is to your JS Error handling script, and if so, ignore it.

$("html").ajaxError(function (event, jqXHR, ajaxSettings, thrownError){
    if (ajaxSettings.url.substring(0,len)=='http://www.example.com/logJSError') {
        return;
    }
});