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Editorial Team
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Asked: 2026-06-06T17:25:01+00:00

<html> <body> <form action=login.do method=post> //….. <input type=submit value =send> </form> </body> </html> In

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<html>
<body>

    <form action="login.do" method="post">
        //.....

        <input type="submit" value ="send">
    </form>
</body>
</html>

In my servlet I will be handle the request and send the json response back.
How can I get the json object from the response ?

But we can do this by calling a function when we click the button.

function(){
    $ajax(
        url:"login.do"
        success: function(data){
        //..... 
        }
    )
}

is there any way to do this? Or only using the function call we can do it?

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1 Answer

  1. Editorial Team

    first argument of success callback that you call data is the json object so long as you include dataType:'json' in ajax options or use shorthand $.post(url[,data][,function(json){}),'json']) method

    Read about success callback in $.ajax API :

    http://api.jquery.com/jQuery.ajax/

    EDIT: Using deffered method

    var ajaxCall= $.post( url, dataToServer,'json')


 $.when( ajaxCall).then(function(data){
     var json =data;
 })
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