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Editorial Team
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Asked: 2026-06-15T10:09:09+00:00

<html> <body> <?php include ‘index.php’; include ‘../db.php’; $query_email = SELECT email FROM email_addresses; $result_query_email

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<html>
<body>
<?php

include 'index.php';
include '../db.php';
$query_email = "SELECT email FROM email_addresses"; 
$result_query_email = mysqli_query($query_email)
or die(mysqli_error());

while ($row = mysqli_fetch_array()($result_query_email)) {

//$email_user = $row[10];
$email_user = $row['email'];

$data = date("Y.m.d");
$subject = "Good news";
$message = ("Hello!");

$sentemail = mail($email_user, $subject, $message, 
"From: abc <xyz.com>\nX-Mailer: PHP/" . phpversion());
}
if($sentemail) 
{

    print("Email has been sent successfully.<br>");
}
else
{
  print("There was a problem while sending email.<br>");
}

?>

</body>
</html>

This code is to select email addresses from the database and to send them an email. what is wrong with my code, i can’t get any email, Help will be appreciated. Thanks!

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1 Answer

  1. Editorial Team

    This line here

    while (mysql_fetch_array($result_query_email)

    you need to assign the return value of mysql_fetch_array() to a variable to be able to use it in the while() loop as well as the missing closing )

    for instance

    while ($emaildata = mysql_fetch_array($result_query_email)) {
{
    $email_user = $emaildata['email'];
 //.....rest of code

    also

    Please, don’t use mysql_* functions in new code. They are no longer maintained and the deprecation process has begun, see the red box. Learn about prepared statements instead, and use PDO or MySQLi; this article will help you decide which. If you choose PDO, here is a good tutorial.

    EDIT

    Also it seems like you are trying to use the variable as a associative array you need to use mysql_fetch_assoc() instead of mysql_fetch_array() to do that

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