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Home/ Questions/Q 3961146
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T02:56:24+00:00 2026-05-20T02:56:24+00:00

<html> <head> <title> Register </title> </head> <body> Thanks for showing interest, please register below.

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<html>
<head>
<title> Register </title>
</head>
<body>

Thanks for showing interest, please register below.
<br>


<br/>
<form action="register.php" method="POST">
Username: <input type="text" name="username">
<br>

</br>
Password: <input type="password" name="password">
<br>

</br>
Age:      <input type="text" name="age">
<br>

</br>
Car:      <input type="text" name="car">
<br>


<input type="submit" value="register"/>
<input type="reset" value="Reset fields"/>
</form>

<?php

    //db connect
    $host="localhost"; 
    $dbuser="site1login";
    $dbpass="site1login";
    $dbname="login";
    $tblname="userdata";

    //form post
    $Username=$_POST['username'];
    $Password=$_POST['password'];
    $Age=$_POST['age'];
    $Car=$_POST['car'];
    $con = mysql_connect("$host","$dbuser","$dbpass") or die (mysql_error());

    mysql_select_db($dbname, $con);

    $result = mysql_query("INSERT INTO `userdata` (Username,Password,Age,Car) VALUES ($Username, $Password, $Age, $Car)" or die(mysql_error()));
    echo "Success!";

?>

</body>

</html>

So, that’s my code – I’m confused – it doesn’t work – it says “success”, but not inserted e anything

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T02:56:24+00:00Added an answer on May 20, 2026 at 2:56 am

    Change the following portion –

    $result = mysql_query("INSERT INTO `userdata` (Username,Password,Age,Car) VALUES 
                 ($Username, $Password, $Age, $Car)" or die(mysql_error()));
    echo "Success!";
    

    into this –

    $result = mysql_query("INSERT INTO userdata (Username,Password,Age,Car) VALUES 
              ('$Username', '$Password', '$Age', '$Car')");
    
    if($result)
    {
        echo "Success!";
    }
    else
    {
        die(mysql_error());    // Thanks to Pekka for pointing this out.
    }
    

    If the above doesn’t work, try checking if your connection parameters are ok and if MySQL is running.

    Also you should test the $resut value to check whether any successful query execution has occured –

    if($result)
    {
        // Successful query execution
    }
    else
    {
        // Some error occured while executing query.
        // Show some useful information using echo/print.
        // Then stop execution after taking other necessary steps
    }
    

    Edit

    As Pekka has mentioned, your database is vulnerable to SQL Injection attack since you are not sanitizing your input. You should use at least mysql_real_escape_string method to ensure that this doesn’t occur.

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