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Editorial Team
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Asked: 2026-06-11T21:51:52+00:00

<html> <head><title></title></head> <body> <?php if (isset ($_POST[‘posted’])) { if ($_POST[‘question1’] == Lisbon) { echo

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<html>
<head><title></title></head>
<body>
<?php
if (isset ($_POST['posted'])) {
if ($_POST['question1'] == "Lisbon") {
  echo "You are correct, $_POST[question1] is the right answer<hr>";
}

if ($_POST['question1'] != "Lisbon") {
  echo "You are incorrect, $_POST[question1] is not. the right answer<hr>";
}
}
?>
<form method="POST" action="quiz.php">
<input type="hidden" name="posted" value="true">
What is the capital of Portugal?
<br>
<br>
<input name=''question1" type=''radio" value=''Porto''>
Porto
<br>
<input name=''question1" type="radio" value=''Lisbon''>
Lisbon
<br>
<input name="question1" type="radio" value=''Madrid''>
Madrid
<br>
<br>
<input type=''submit''>
</form>
</body>
</html>

This is the whole part, it’s from a PDF. Thing is though, they didn’t specified why they used ‘ ‘ for the question1 in the if statement but no quotes in the echo statement.

In a nutshell: why $_POST[‘question1’] has ‘ ‘ in the if statement
and why $_POST[question1] doesn’t have in the echo statement. They are the same variable.
Thank you.

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1 Answer

  1. Editorial Team

    Always use quotes (for string keys), unless inside a double quoted string. See the string parsing section of the manual.

    $juices = array("apple", "orange", "koolaid1" => "purple");

echo "He drank some $juices[0] juice.".PHP_EOL;
echo "He drank some $juices[1] juice.".PHP_EOL;
echo "He drank some juice made of $juice[0]s.".PHP_EOL; // Won't work
echo "He drank some $juices[koolaid1] juice.".PHP_EOL;
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