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Home/ Questions/Q 6578517
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:46:51+00:00 2026-05-25T15:46:51+00:00

Hy, I have started working with threads in C++ (boost threads), and I have

  • 0

Hy,

I have started working with threads in C++ (boost threads),
and I have found my self in the following situation:

boost::mutex::scoped_lock lk(monitor);
while (buffered == 0) {
    buffer_not_empty.wait(lk);
}

And I was wandering if the int variable buffered should be volatile.
I would say that it should, to prevent a optimization like this, at compile time:

boost::mutex::scoped_lock lk(monitor);
while (true) {
    buffer_not_empty.wait(lk);
}

but since this is a example from the boost documentation, I may be missing something…

is a lock/mutex/condition enough to prevent this kind of optimizations ? like in java ?

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:46:52+00:00Added an answer on May 25, 2026 at 3:46 pm

    You need not mess with volatile. volatile has absolutely nothing to do with multithreading. Even if the compiler doesn’t optimize things away to the loop you mention somehow, your CPU might make the same optimization, and volatile does not affect the CPU.

    wait should contain the necessary memory barrier instructions required make this operate as expected.

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