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Home/ Questions/Q 7723041
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T04:20:34+00:00 2026-06-01T04:20:34+00:00

Hy … I have the following code : try { Nrtrde record = new

  • 0

Hy … I have the following code :

    try { Nrtrde record = new Nrtrde(); }
    catch (Exception e) {
        System.out.println(" ERROR\n");
        e.printStackTrace(); }
    finally { Nrtrde record = new Nrtrde(); System.out.println(" OK\n"); }

record.setSpecificationVersionNumber(specificationVersionNo);

and when compiling i get the following error :

NRTRDE\ENCODER.java:28: error: cannot find symbol
        record.setSpecificationVersionNumber(specificationVersionNo);
        ^
  symbol:   variable record
  location: class ENCODER
1 error

It seems I cannot create an object insinde a try {} and use it outside try {} ..

Why ?

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T04:20:36+00:00Added an answer on June 1, 2026 at 4:20 am

    You have to declare it outside the block, but you can initialize it inside the block:

    Nrtrde record = null;
    try { 
        record = new Nrtrde();
    } catch (SomeException e) {
        // handle exception here
    }
    if(record!=null){
        // do something with it
    }
    

    In Java, {} are block delimiters. Nothing is visible outside the block it is defined in. (Class members are an exception to this rule if the visibility allows it).

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