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Home/ Questions/Q 884733
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T12:47:39+00:00 2026-05-15T12:47:39+00:00

//Hydroelectric Dam Helper #include <stdio.h> #define GRAV 9.80 #define EFINC 0.9 #define EFINC2 90

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//Hydroelectric Dam Helper
#include <stdio.h>
#define GRAV 9.80
#define EFINC 0.9
#define EFINC2 90


int main()
{
  //Defines all the variables to be used
  double height, work, mass;
  printf("Height of dam (in meters):");
  scanf("%lf", &height);
  printf("Flow of water (in thousand cubic meters per second):");
  scanf("%lf", &mass);
  work = (mass * GRAV * height * EFINC); 
  printf("The dam would produce %f megawatts at %d%% efficency", &work, EFINC2);
  return 0; 
}

The values set correctly, I tested it by having it print height and mass but work never receives a value, and EFINC2 prints out a ridiculous number that I’m not really sure about

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  1. Editorial Team
    Editorial Team
    2026-05-15T12:47:39+00:00Added an answer on May 15, 2026 at 12:47 pm
    printf("The dam would produce %f megawatts at %d%% efficency", &work, EFINC2);
    

    should read:

    printf("The dam would produce %f megawatts at %d%% efficency", work, EFINC2);
    

    &work is a pointer to work, i.e. a double* but for printf to print the value you need to pass a double and not a pointer. On your platform a double* is probably a different size to a double causing the subsequent printf formats to use the wrong data.

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