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Home/ Questions/Q 8592689
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T23:48:37+00:00 2026-06-11T23:48:37+00:00

Hye! This is my first question here, so sorry in advance if I don’t

  • 0

Hye! This is my first question here, so sorry in advance if I don’t get it right.

I want to insert pictures from a gallery in a description text by using #pic1# (#pic2# and so on) in the text and replace it with

Here is the code:

<?
$myString =$art[0][page_text];
$pics=mysql_query_assoc("select * from pages_galerie where id_page='".$id_page."'");
$count= count($pics);
for ($i=0; $i < $count; $i++) {
$search='#pic'.$i+1.'#';
$img=$pics[$i][pic];
$newString = str_replace($search, "<img src=".SITE_URL."pics/medium/".$img.">", $myString);
}
?>

It doesn’t work!
What do I do wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T23:48:38+00:00Added an answer on June 11, 2026 at 11:48 pm

    Try this
    http://codepad.org/2NBlkDN9

    <?
    $myString =$art[0][page_text];
    $myString = '#pic1# #pic2#';
    //$pics=mysql_query_assoc("select * from pages_galerie where id_page='".$id_page."'");
    $pics = array(
       array('pic' => 'TEST1'),
       array('pic' => 'TEST2'),
       array('pic' => 'TEST3'),
    );
    $count= count($pics);
    
    $newString = $myString;
    for ($i=0; $i < $count; $i++) {
    $search='#pic'.($i+1).'#';
    $img=$pics[$i][pic];
    
    $newString = str_replace($search, "<img src=".SITE_URL."pics/medium/".$img.">", $newString);
    }
    echo $newString;
    ?>
    

    You were performing the replacement in $myString and storing it in $newString everytime. Hence only the last replacement had any effect on the final output. I have initialzed $newString with $myString and performed the replacement in $newString.

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