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Home/ Questions/Q 8405461
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T22:51:31+00:00 2026-06-09T22:51:31+00:00

I already have the code ready but my limited jQuery skills, if any, can’t

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I already have the code ready but my limited jQuery skills, if any, can’t help me figure out why the output I want can’t be achieved.

Here’s the jQuery code:

 $('#property_types option').slice(1).each(
 function(){
var text = $(this).text(),
    outputTo = $('#output'),
    div = $('<div />', {'class' : text}).text(text),
    href = $('<a />', {'href' : '#', 'onclick' : 'go'+text+'();'}).prependTo(div),
    img = $('<img />', {'src' : 'images/'+text+'.png', 'style' : 'vertical-align:middle;padding-right:5px', 'width' : '35'}).prependTo(href);
div.appendTo(outputTo);
 });

and here’s the output it currently gives:

 <div id="output">
 <div class="Apartment">
 <a href="#" onclick="goApartment();">
 <img src="images/Apartment.png" style="vertical-align: middle; padding-right: 5px; width: 35px;">
 </a>
 Apartment
 </div>

The problem is, the text AKA “Apartment” is being left out of the link. how can I fix this without hurting the current functions of the code? Any help is appreciated. Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T22:51:32+00:00Added an answer on June 9, 2026 at 10:51 pm

    Try this:

    $('#property_types option').slice(1).each(function(){
        var text = $(this).text(),
        outputTo = $('#output'),
        div = $('<div />', {'class' : text});
        href = $('<a />', {'href' : '#', 'onclick' : 'go'+text+'();'}).text(text).prependTo(div),
        img = $('<img />', {'src' : 'images/'+text+'.png', 'style' : 'vertical-align:middle;padding-right:5px', 'width' : '35'}).prependTo(href);
        div.appendTo(outputTo);
     });
    
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