Question

I always have trouble mixing languages and I recently started with MYSQL. In this case I have this code:

<?php
 $data = mysql_query("SELECT * FROM Badges") 
 or die(mysql_error()); 
 while($info = mysql_fetch_array( $data )) 
 { 
 Print "http://www.google.com/s2/favicons?domain=".$info['Website'] . ""; 
 } 
?>

And I need it to print an image instead of the link it’s printing.

http://www.google.com/s2/favicons?domain=“.$info[‘Website’] . ” being the image’s url

How would that be written? Thanks a lot

Answer 1

print '<img src="http://www.google.com/s2/favicons?domain=' . $info['Website'] . '" alt="" />'; 

Some other tips…

• mysql_* are old functions, PDO is much better to use now it is available.
• or die() is old too – have you considered exceptions?
• echo is more commonly used than print, and you should use the case that is stated in the manual, e.g. print instead of Print.
• You should learn about separation of concerns, e.g. you should do your query and data management on a different layer where you pass the relevant data to your view which would consist solely of HTML and some PHP constructs used to generate it.