Question

I am a beginner in php my code to create a directory is given below.

<?php


        if($_POST["create"])
        { 
            $name=$_POST["newDirCreated"];
            $uploaddir = $name;
            mkdir($uploaddir,0777);
            print "created";
        }


?>

But directory is not created using this. If i want create a directory in public_html how can i do it?

Answer 1

mkdir() doesn’t throw an exception when something goes wrong. You have to make your script a little bit more “talkative” to get more information about what’s going on

<?php
error_reporting(E_ALL);
ini_set('display_errors', true);

if( !isset($_POST["create"]) ) {
    echo 'post parameter create not present';
}
else {
    // you are absolutely sure about passing the POST parameter as-is to mkdir() ?
    // ok, it's up to you; just make sure it doesn't get abused....
    echo 'current working directory: ', htmlspecialchars(getcwd()), "<br />\n";
    echo 'newDirCreated: ', htmlspecialchars($_POST["newDirCreated"]), "<br />\n";
    $rc = mkdir($_POST["newDirCreated"], 0777);
    if ( $rc ) {
        echo 'created';
    }
    else {
        echo "an error occured<br />\n";
        if ( function_exists('error_get_last') ) {
            echo 'error_get_last: ', htmlspecialchars(print_r(error_get_last(), true));
        }
        else if ( isset($php_errormsg) ) {
            echo 'php_errormsg: ', htmlspecialchars($php_errormsg);
        }
        else {
            echo 'no additional error information available';
        }
    }
}

But remember to make it less talkative (yet handling error conditions) again after debugging. You shouldn’t expose all the inforamtion to arbitrary users…

see also:

• http://docs.php.net/reserved.variables.phperrormsg
• http://docs.php.net/error_get_last