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Home/ Questions/Q 6596945
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Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T18:08:41+00:00 2026-05-25T18:08:41+00:00

I am a bit confused right now. I have a J2ME app that sends

  • 0

I am a bit confused right now.

I have a J2ME app that sends POST requests to a servlet. It was working up until miraculous this morning it stopped working. It just won’t send the POST data. It will contact the server, but the request data will be empty.

System.out.println(request.getParameterMap());

Always returns

{}

I tried to check the network monitor from the emulator and I saw this

sq~wLhttp://localhost:80802xѬ2xѬ????????xsq~wLhttp://localhost:80802xѬ2xѭ????????xsq~z?http://localhost:80802xѬK2xѬ????????1316274753996
POST /amw/synch HTTP/1.1
User-Agent: Profile/MIDP-1.0 Confirguration/CLDC-1.0 UNTRUSTED/1.0
Accept_Language: en-US
Content-Type: application/x-www-form-urlencoded
Host: localhost:8080
Transfer-Encoding: chunked

56
&action=recover&email=trinisoftinc@gmail.com&password=1011001&api-key=oalkuisnetgauyno
0

xsq~z?http://localhost:80802xѬD2xѭ????????1316274754009
HTTP/1.1 200 OK
X-Powered-By: Servlet/3.0 JSP/2.2 (GlassFish Server Open Source Edition 3.1 Java/Apple Inc./1.6)
Server: GlassFish Server Open Source Edition 3.1
Content-Type: text/html;charset=UTF-8
Content-Length: 46
Date: Sat, 17 Sep 2011 15:52:33 GMT

{"message":"Server Error: null","status":500}

I didn’t know what to make of it really.

Please I need help.

The code sending the request is below

public String post(String url, String query, String optionalParameters) throws IOException {
    if (optionalParameters != null) {
        url += optionalParameters;
    }

    query += "&api-key=" + APIKey;
    Echo.outln(url + ", " + query.getBytes().length);
    Echo.outln(query);
    HttpConnection connection;
    connection = (HttpConnection) Connector.open(url);

    connection.setRequestMethod(HttpConnection.POST);
    connection.setRequestProperty("User-Agent", "Profile/MIDP-1.0 Confirguration/CLDC-1.0");
    connection.setRequestProperty("Accept_Language", "en-US");
    connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
    connection.setRequestProperty("Content-Length", String.valueOf(query.getBytes().length));
    //connection.setRequestProperty("api-key", APIKey);

    OutputStream os = connection.openDataOutputStream();
    os.write(query.getBytes());
    os.flush();
    if (connection.getResponseCode() == HttpConnection.HTTP_OK) {
        InputStream is = connection.openInputStream();
        int ch;
        StringBuffer buffer = new StringBuffer();

        while((ch = is.read()) != -1) {
            buffer.append((char) ch);
        }            

        try {
            is.close();
            connection.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return buffer.toString();
    } else {
        String retval = connection.getResponseMessage() + " : " + connection.getResponseCode();
        try {
            connection.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return retval;
    }
}

Thanks.

NB: I have an iPhone app that calls the same servlet and works perfectly well.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:08:42+00:00Added an answer on May 25, 2026 at 6:08 pm

    So case matters. This post Http post from J2ME saved my life.

    The offending line is

    connection.setRequestProperty("Content-Length", "" + query.getBytes().length);
    

    Instead of

    connection.setRequestProperty("Content-length", "" + query.getBytes().length);
    

    NOTE: Small letter l, not capital letter L.

    After that change, the world looks beautiful again

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