Question

I am a bit lost when it comes to retrieving results from the database.

My MemberModel consists of 4 fields: id, username, password and email. I have been able to successfully save it to database.

Now I need to retrieve an id of a member who’s username equals “Test”.

I tried something along the lines:

SQLQuery query = session.createSQLQuery("SELECT id FROM members WHERE username = :username");
query.setString("username", username);
List<MemberModel> returnedMembers = query.list();
MemberModel member = returnedMembers.get(0);
int id = member.getId();

However I get an error that member.getId() cannot be converted to int, since it is MemberModel… But the getter getId() returns int.

I am quite confused. The question is: what would be the easiest and fastes way to retrieve member id based on condition (value of username)?

Answer 1

I would change your code into something like this:

public MemberModel getMember(String username) {
    Query query = sessionFactory.getCurrentSession().createQuery("from  " + MemberModel.class.getName() + " where username = :username ");
    query.setParameter("username", username);
    return (MemberModel) query.uniqueResult();
}

Then you should be able to do:

MemberModel model = someInstance.getMember("someUsername");
int id = model.getId();