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Home/ Questions/Q 6613479
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T20:13:24+00:00 2026-05-25T20:13:24+00:00

I am a bit new at this and totally messing something up. I have

  • 0

I am a bit new at this and totally messing something up. I have a PHP result set through which I iterate like this:

    $rows = array();
    while($r = mysql_fetch_assoc($result))
    {
        $rows[] = $r;
    }

    echo json_encode($rows);

and then I output it like this in jQuery code:

success: function(json)
            {
                $('.success').fadeIn(200).show();
                $('.error').fadeOut(200).hide();

                // Here can update the right side of the screen with the newly entered information
        alert (json);

        var ob = $.parseJSON(json);

            alert (ob.creator_member_id);
            alert (ob.problem_title);
            alert (ob.problem_description);
            alert (ob.problem_date);


            }

But there is an error on the var ob = $.parseJSON(json); line it seems. My JS console gives this error:

Uncaught TypeError: Object function (D,E){return new n.fn.init(D,E)} has no method 'parseJSON'

What can this mean and how can I fix this?

Thanks!!

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  1. Editorial Team
    Editorial Team
    2026-05-25T20:13:24+00:00Added an answer on May 25, 2026 at 8:13 pm

    If you are getting JSON results via jQuery ajax call you don’t need parsing resultant json – jQuery does it for you.

    Just specify the

    dataType: 'json'
    

    [http://api.jquery.com/jQuery.ajax/], and your success handler will have the already parsed object.

    If you want parsing JSON anywhay, try adding json2.js to your project. You’ll have to call JSON.parse(json) then.

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