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Home/ Questions/Q 9314473
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Editorial Team
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Editorial Team
Asked: June 19, 20262026-06-19T02:08:31+00:00 2026-06-19T02:08:31+00:00

I am a little bit confused by the jQuery documentation. I am looking at

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I am a little bit confused by the jQuery documentation. I am looking at this page describing $.getJSON. The code sample is:

$.getJSON('ajax/test.json', function(data) {
  var items = [];

  $.each(data, function(key, val) {
    items.push('<li id="' + key + '">' + val + '</li>');
  });

  $('<ul/>', {
    'class': 'my-new-list',
    html: items.join('')
  }).appendTo('body');
});

But the method signature is jQuery.getJSON( url [, data ] [, success(data, textStatus, jqXHR) ] ), where data is an object sent to the server, and success is a method called when the JSON request returns successfully.

So why does the example code work? It seems to have skipped the second argument. I would have expected the correct code to be:

$.getJSON('ajax/test.json', {}, function(data) {
// and then the same from here

I know that the square brackets mean that the [, data] and [, success] arguments are optional, but I guess I don’t understand how javascript deals with a variable number of arguments.

Thank you for your time.

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  1. Editorial Team
    Editorial Team
    2026-06-19T02:08:32+00:00Added an answer on June 19, 2026 at 2:08 am

    Inside the jQuery source code :

    // shift arguments if data argument was omitted
            if ( jQuery.isFunction( data ) ) {
                type = type || callback;
                callback = data;
                data = undefined;
            }
    

    So it works

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