Question

I am a python newbie. I was confused on how to access array element dynamically.

I have a list b= [1,2,5,8] that I dynamically obtain so its length can vary. With help of this list I need to update multi-dimensional array as mArr[1] [2] [5] [8] . The length of the list and array dimension matches as given in the example

Basically, I am looking a technique to access a multi dimensional array with respect to the list “b” as in the form of : marr[b]. This m-array is also dynamically created.

I tried looking on to tutorials of numpy but was not figure out the solution.Am I missing something?

Thanks in advance.

Answer 1

if the dimensions are [1,2,5,8] you can use numbers 0, 0..1, 0..4, 0..7 for each dimension.

Numpy lets you access positions with tuples:

shape = [1, 2, 5, 8]
pos = [0, 1, 1, 3]

my_array = np.ones(shape)
my_array[tuple(pos)] # will return 1