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Home/ Questions/Q 7871283
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T01:51:20+00:00 2026-06-03T01:51:20+00:00

I am able to use SWIG_NewPointerObj to pass a C++ object to Python, but

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I am able to use SWIG_NewPointerObj to pass a C++ object to Python, but it’s not the PyObject* so I can’t use it properly in Python.

My question is: Is there a way to fetch the PyObject* of a C++ object that was created from Python, in C++?

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  1. Editorial Team
    Editorial Team
    2026-06-03T01:51:21+00:00Added an answer on June 3, 2026 at 1:51 am

    There isn’t a unique PyObject per C++ object. For example if you wrap the following:

    struct foo {};
    
    struct foo *test() {
      static struct foo inst;
      return &inst;
    }
    

    Every call to test() inside Python will return a new PyObject – SWIG has no easy way to know they’re identical.

    The PyObjects that get returned are thin wrappers, i.e. proxies around the C++ object that have no local state. From the Python perspective these all look and behave like the same object because they delegate everything to the C++ object.

    If you want to get hold of a PyObject there are ways you can do this, but in general it’s not a good idea because any changes you make to that object won’t be visible from other PyObjects even if they refer to the same C++ object.

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