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Home/ Questions/Q 8655927
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Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T15:09:20+00:00 2026-06-12T15:09:20+00:00

I am adding the new module in some large library. All methods here are

  • 0

I am adding the new module in some large library. All methods here are implemented as static. Let me briefly describe the simplified model:

typedef std::vector<double> TData;
double test ( const TData &arg ) { return arg ( 0 ) * sin ( arg ( 1 ) + ...;}
double ( * p_test ) ( const TData> &arg) = &test;

class A
{
    public:
      static T f1 (TData &input) {
         .... //some computations
         B::f2 (p_test);
      }
};

Inside f1() some computations are performed and a static method B::f2 is called. The f2 method is implemented by another author and represents some simulation algorithm (example here is simplified).

class B
{
    public:
      static double f2 (double ( * p_test ) ( const TData  &arg ) )
      {
          //difficult algorithm working p_test many times
          double res = p_test(arg);
      }
};

The f2 method has a pointer to some weight function (here p_test). But in my case some additional parameters computed in f1 for test() methods are required

 double test ( const TData &arg, const TData &arg2, char *arg3.... ) { }

How to inject these parameters into test() (and so to f2) to avoid changing the source code of the f2 methods (that is not trivial), redesign of the library and without dirty hacks 🙂 ?

The most simple step is to override f2

static double f2 (double ( * p_test ) ( const TData  &arg ), const TData &arg2, char *arg3....  )

But what to do later? Consider, that methods are static, so there will be problems with objects.


Updated question

Is it possible to make a pointer to a function dependent on some template parameter or do something like that

if (condition) res = p_test(arg);
else res = p_test2(arg, arg2, arg3);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T15:09:21+00:00Added an answer on June 12, 2026 at 3:09 pm

    without dirty hacks

    Not gonna happen. If you can’t modify the source of a function taking a function pointer, you’ll have to use an exception vomit to gain the extra arguments. If you had a C++11 compiler (that does not exist yet) which supports thread_local, it’s theoretically possible to do something better, or you could use OS-specific TLS. But as of right now, the only portable solution is an exception vomit.

    void f(void(*fp)()) { fp(); }
    void mah_func() { 
        try { 
            throw; 
        } catch(my_class* m) {
            m->func();
        }
    }
    int main() {
        my_class m;
        try {
            throw &m;
        } catch(my_class* p) {
            f(mah_func);
        }
    }
    

    Alternatively, in your scenario, modifying f2 doesn’t seem to be impossible, only difficult. However, the difficulty of altering it to take a std::function<double(const TData&)> would be very low- all you’d have to do is change the argument type, thanks to operator overloading. It should be a very simple change for even a complex function, as you’re only changing the type of the function parameter, all the call sites will still work, etc. Then you can pass a proper function object made through bind or a lambda or somesuch.

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