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Editorial Team
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Asked: 2026-05-14T01:19:42+00:00

I am appending new data – $(‘#posts’).append(data); But I want this new data to

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I am appending new data – $(‘#posts’).append(data);
But I want this new data to .slideToggle() while appending.

How can it be done?

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1 Answer

  1. Editorial Team

    You can do it if you have a single containing element.

    $("<div>").append(data).hide().appendTo("#posts").slideDown();

    Let me give you an example:

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.0/jquery.min.js"></script>
<script type="text/javascript">
var content = '<p>four</p><p>five</p><p>six</p>';
$(function() {
  $("#add").click(function() {
    $("<div>").append(content).hide().appendTo("#container").slideDown(1000, function() {
      $(this).contents().unwrap();
    });
  });
});
</script>
<style type="text/css">
div, p { padding: 0; margin: 0; border: 0 none; }
#container { background: yellow; border: 1px solid black; }
</style>
</head>
<body>
<div id="container">
<p>one</p>
<p>two</p>
<p>three</p>
</div>
<input id="add" type="button" value="Add Content">
</body>
</html>

    Here the content is not one block, it’s three (paragraphs). If it was one block you wouldn’t need to wrap it like this.

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