Question

I am attempting to optimize a query where I want a “close enough” response.

I have two sets: A and B.

Set A contains 1, 2, 3, 5, 6, 7, 8
Set B contains 1, 2, 3, 4

What I’d like to do is check B against A in such a way that it would tell me that 1 element is missing (4 in this case).

Is there a cleaner, more efficient way of doing this besides just going element by element and comparing?

Answer 1

NSMutableSet *resultSet = [NSMutableSet setWithArray:B];
NSSet *setA = [NSSet setWithArray:A];
[resultSet minusSet:setA];
Array *result = [resultSet allObjects];

Reference : NSMutableSet