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Home/ Questions/Q 731225
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:00:08+00:00 2026-05-14T07:00:08+00:00

I am attempting to pase a a JSON data using the JQuery getJSON function.

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I am attempting to pase a a JSON data using the JQuery getJSON function.
The REST query is:

http://query.yahooapis.com/v1/public/yql?q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22london%22&format=json&jsoncallback=?

The script I’m using to parse ‘data’ to obtain the WOEID value doesnt seem to work below:

 $.getJSON("http://query.yahooapis.com/v1/public/yql?"+
                "q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22"+
                "london"+
                "%22&format=json&jsoncallback=?",
        function(data){
  console.log("json: " + data);
  var datatmp = data;
          if(data.results[0]){
            var data = filterData(data.results.place[0]);
           }
         }
       );

Can anyone say what I’m doing wrong?
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  1. Editorial Team
    Editorial Team
    2026-05-14T07:00:08+00:00Added an answer on May 14, 2026 at 7:00 am

    Your code needed a few tweaks, here’s an updated version:

    $.getJSON("http://query.yahooapis.com/v1/public/yql?"+
          "q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22"+
          "london"+
          "%22&format=json&jsoncallback=json",
          function(data){
              if(data.query.results){
                  $.each(data.query.results.place, function(i, v) {
                      console.log("woeid #" + i + ": " + v["woeid"]);
                  });
              }
          });​
    

    The results object is beneath query, so you need to go into there first, the above code iterates through the woeid’s of the first place returned and alerts them…it’s just a starter, not sure what you ultimately wanted to do with the woeid but hopefully this will get you started. You can see the above code working here.

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