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Asked: May 10, 20262026-05-10T21:03:02+00:00 2026-05-10T21:03:02+00:00

I am attempting to write a one-line Perl script that will toggle a line

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I am attempting to write a one-line Perl script that will toggle a line in a configuration file from ‘commented’ to not and back. I have the following so far:

perl -pi -e 's/^(#?)(\tDefaultServerLayout)/ ... /e' xorg.conf 

I am trying to figure out what code to put in the replacement (…) section. I would like the replacement to insert a ‘#’ if one was not matched on, and remove it if it was matched on.

pseudo code:

if ( $1 == '#' ) then    print $2 else    print '#$2' 

My Perl is very rusty, and I don’t know how to fit that into a s///e replacement.

My reason for this is to create a single script that will change (toggle) my display settings between two layouts. I would prefer to have this done in only one script.

I am open to suggestions for alternate methods, but I would like to keep this a one-liner that I can just include in a shell script that is doing other things I want to happen when I change layouts.

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  1. 2026-05-10T21:03:02+00:00Added an answer on May 10, 2026 at 9:03 pm
    perl -pi -e 's/^(#?)(?=\tDefaultServerLayout)/ ! $1 && '#' /e' foo 

    Note the addition of ?= to simplify the replacement string by using a look-ahead assertion.

    Some might prefer s/…/ $1 ? ” : ‘#’ /e.

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