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Home/ Questions/Q 6611529
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:58:52+00:00 2026-05-25T19:58:52+00:00

I am basically looking for an XSLT (say a callable template), which will take

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I am basically looking for an XSLT (say a callable template), which will take as input an xml AND an element to be deleted in the XML and give me back the final XML after deleting that particular element in the XML.

Example:

<Request>
  <Activity1>XYZ</Activity1>
  <Activity2>ABC</Activity2>
</Request>

Now i need an xslt for which i must give the above xml as input and the element to be deleted (Say <Activity1>) as input. The XSLT must return the final xml after deleting the element passed to it.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:58:52+00:00Added an answer on May 25, 2026 at 7:58 pm

    You can use a modified copy-template:

    <xsl:stylesheet ...>
       <xsl:output method="xml" encoding="UTF-8" indent="yes"/>
    
       <xsl:variable name="removeNode">Activity1</xsl:variable>
    
       <xsl:template match="node()">        
         <xsl:if test="not(name()=$removeNode)">
           <xsl:copy>
              <xsl:apply-templates select="@*|node()"/>
           </xsl:copy>
         </xsl:if>
       </xsl:template>
    
       <xsl:template match="@*">        
         <xsl:copy>
           <xsl:apply-templates select="@*"/>
         </xsl:copy>
       </xsl:template>
    </xsl:stylesheet>
    

    How to pass the parameter to yout template depends on your used XSLT-processor.

    Edit

    Another possibility is to ignore the node when needed:

    <xsl:template match="/">
      <xsl:apply-templates select="*/*[not(self::element-to-ignore)]" 
                           mode="renderResult"/>
    </xsl:template>
    
    <xsl:template match="@*|node()" mode="renderResult">
      <xsl:copy>
        <xsl:apply-templates select="@*|node()" mode="renderResult"/>
      </xsl:copy>
    </xsl:template>
    
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