Question

I am begginer to android development. I am using SAX parser for xml parser. I couldn’t find the reason for this exeption.
I tried getAsset() method. but it didn’t worked.

xmlParser code :::

 public class XMLParser {

     public static Country parseCountry(InputStream is) {
        try {
         Country country= new Country(null, null, null);

         XMLReader xmlReader =  SAXParserFactory.newInstance().newSAXParser().getXMLReader();
         XMLHandler xmlHandler = new XMLHandler();
         xmlReader.setContentHandler(xmlHandler);     
         xmlReader.parse(new InputSource(new FileInputStream(http://64.85.165.53/dharatest/xmlarray.xml));
         country = xmlHandler.getParsedCountryData();

        } catch(ParserConfigurationException pce) { 
               Log.e("SAX XML", "sax parse error", pce); 
        } catch(SAXException se) { 
               Log.e("SAX XML", "sax error", se);       
        } catch(IOException ioe) { 
               Log.e("SAX XML", "sax parse io error", ioe); 
        }     
       return country;
   }
 }

Answer 1

Why are you using a FileInputStream with a URL? Try:

 public class XMLParser {

     public static Country parseCountry(InputStream is) {
        try {
         Country country= new Country(null, null, null);

         XMLReader xmlReader =  SAXParserFactory.newInstance().newSAXParser().getXMLReader();
         XMLHandler xmlHandler = new XMLHandler();
         xmlReader.setContentHandler(xmlHandler);     
         xmlReader.parse(new InputSource(new URL("http://64.85.165.53/dharatest/xmlarray.xml").openStream());
         country = xmlHandler.getParsedCountryData();

        } catch(ParserConfigurationException pce) { 
               Log.e("SAX XML", "sax parse error", pce); 
        } catch(SAXException se) { 
               Log.e("SAX XML", "sax error", se);       
        } catch(IOException ioe) { 
               Log.e("SAX XML", "sax parse io error", ioe); 
        }     
       return country;
   }
 }