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Home/ Questions/Q 6929295
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:17:55+00:00 2026-05-27T11:17:55+00:00

I am binding a textbox to an object, like so: <TextBlock d:DataContext={d:DesignInstance ViewModel:TaskVM }

  • 0

I am binding a textbox to an object, like so:

  <TextBlock d:DataContext="{d:DesignInstance ViewModel:TaskVM }" 
             Text="{Binding Title}" MouseLeftButtonDown="TextBlock_MouseLeftButtonDown">
  </TextBlock>

Now I am wondering how to make it display mock data during design. I’ve tried doing something like that:

  <TextBlock Text="{Binding Path=Title}" MouseLeftButtonDown="TextBlock_MouseLeftButtonDown">
    <d:DesignProperties.DataContext>
       <ViewModel:TaskVM Title="Mock"/>
    </d:DesignProperties.DataContext>
  </TextBlock>

However, since TaskVM has no default ctor, I am getting a “No default constructor” found.

I know that when I use d:DataContext="{d:DesignInstance ViewModel:TaskVM }" it creates a mock data type. Is there a way for me to set the properties of this mock type?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:17:56+00:00Added an answer on May 27, 2026 at 11:17 am

    The default constructor is required for a type to be instantiated in XAML. As a workaround you can simply create a subclass of TaskVM that will have the default contructor and use it as a design time data context.

    <TextBlock d:DataContext="{d:DesignInstance ViewModel:DesignTimeTaskVM }" 
               Text="{Binding Title}" MouseLeftButtonDown="TextBlock_MouseLeftButtonDown">
    </TextBlock>
    

    Another alternative is to set d:IsDesignTimeCreatable to False and a substitute type will be created for you at runtime (using your TaskVM type as a “shape”).

    <TextBlock d:DataContext="{d:DesignInstance ViewModel:DesignTimeTaskVM, IsDesignTimeCreatable=False}" 
               Text="{Binding Title}" MouseLeftButtonDown="TextBlock_MouseLeftButtonDown">
    </TextBlock>
    
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