Question

I am blocked on a hard request to my database in php….

I would lik to display on my page a list the 10 persons (name/surname) that :
– have answered “1” to 3 questions (question1/question2/question3)
– and have answered at the question4 the closest number of participations (positive or negative sens)

Well i know how to determine my global number of paticipation :

$query_count = "SELECT COUNT(*) AS Nb FROM my_table";    
$result_count = mysql_query($query_count) or die(mysql_error());

while($row = mysql_fetch_array($result_count)){
    echo "Participations :  ". $row['Nb'];
    echo "<br />";
    $count = $row['Nb']; // i create a $count var for next steps

Then i know how to display a request in table :

$query = "SELECT id,name,surname FROM my_table ORDER BY id"; 
$result = mysql_query($query);


// Recuperation des resultats
while($row = mysql_fetch_row($result)){
        $id = $row[0];
        $name = $row[1];
        $surname = $row[2];



        echo "<tr>\n
        <td>$id</td>\n
        <td>$name</td>\n
        <td>$surname</td>\n
        </tr>\n";

    }

But in my $query i don’t know how to say :
show the 10 row WITH name,surname AND answer=1 to question1,2and3 AND
question4 is closer to number of participations (less, equal or more)

Do you have an idea?

Thanks!!!

Answer 1

The first part of your question is elementary: WHERE answer IN (1,2,3) after you make the appropriate join. Since I don’t have your full schema I can’t help with specifics, but here is a rough example:

SELECT u.user_name_first, u.user_name_last FROM user u LEFT JOIN
answers a ON u.user_id = a.user_id WHERE a.answer_id IN (1,2,3);

The second half is vague. Please clarify what you mean by “closer to number of participations (less, equal or more)”.