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Home/ Questions/Q 7798143
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T23:54:51+00:00 2026-06-01T23:54:51+00:00

I am building a function that returns table result ALTER FUNCTION [brm].[fnComputeScores_NEW] ( @var1

  • 0

I am building a function that returns table result

ALTER FUNCTION [brm].[fnComputeScores_NEW]
(
    @var1 TINYINT
)
RETURNS 
@ret TABLE
(
    [producerid] INT
    ,[CityId] INT
    , CityName VARCHAR(100)
)
AS 
BEGIN


INSERT INTO @ret
        SELECT [producerid], [CityId] from producers

--placeholder

RETURN
END

everything is fine to this point

but code that I want to put in placeholder

UPDATE @ret
SET
    CityName = Cities.Name
FROM
    @ret JOIN Cities
        ON @ret.CityId= Cities.CityId

generates compilation error

Must declare the scalar variable “@ret”.

Why? How to fix it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T23:54:53+00:00Added an answer on June 1, 2026 at 11:54 pm

    You can’t reference the table variable outside of FROM. This is not exclusive to UPDATE… from http://msdn.microsoft.com/en-us/library/ms175010.aspx:

    Outside a FROM clause, table variables must be referenced by using an alias…

    …so you can try:

    UPDATE r
    SET
        r.CityName = c.Name
    FROM
        @ret AS r 
        INNER JOIN dbo.Cities AS c
        ON r.CityId = c.CityId;
    
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