Question

I am building a gui for a commandline program.
In txtBoxUrls[TextBox] file paths are entered line by line.
If the file path contains spaces the program is not working properly.
The program is given below.

string[] urls = txtBoxUrls.Text.ToString().Split(new char[] { '\n', '\r' });

string s1;
string text;
foreach (string s in urls)
{
    if (s.Contains(" "))
    {
        s1 = @"""" + s + @"""";
        text += s1 + " ";
    }
    else
    {
        text += s + " ";
    }
}


System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo.CreateNoWindow = true;


proc.StartInfo.FileName = @"wk.exe";


proc.StartInfo.Arguments = text + " " + txtFileName.Text;

proc.StartInfo.UseShellExecute = false;


proc.StartInfo.RedirectStandardOutput = true;


proc.Start();

//Get program output
string strOutput = proc.StandardOutput.ReadToEnd();

//Wait for process to finish
proc.WaitForExit();

For example if the file path entered in txtBoxUrls is “C:\VS2008\Projects\web2pdf\web2pdf\bin\Release\Test Page.htm”, The program will not work. This file path with double quotes will work in the windows command line(I am not using the GUI) nicely.
What would be the solution.

Answer 1

proc.StartInfo.Arguments = text + " " + txtBoxUrls.Text + " " + txtFileName.Text; 

In this line, text already contains the properly quoted version of your txtBoxUrls strings. Why do you add them again in unquoted form (+ txtBoxUrls.Text)? If I understood your code corrently, the following should work:

proc.StartInfo.Arguments = text + " " + txtFileName.Text;    

In fact, since txtFileName.Text could probably contain spaces, you should quote it as well, just to be sure:

proc.StartInfo.Arguments = text + " \"" + txtFileName.Text + "\"";    

(or, using your syntax:)

proc.StartInfo.Arguments = text + @" """ + txtFileName.Text + @"""";