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Home/ Questions/Q 6823365
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:46:26+00:00 2026-05-26T21:46:26+00:00

I am building a .net C# console program to deploy file to a windows

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I am building a .net C# console program to deploy file to a windows file share server (folder that is being shared). The path is :: \\192.168.0.76\htdocs\public

On running I am getting the error:

[09:35:29]: [Step 1/3] Unhandled Exception: System.UnauthorizedAccessException: Access to the path '\\192.168.0.76\htdocs\public' is denied.
[09:35:29]: [Step 1/3]    at DeployFileShare.Program.CopyDir(String source, String dest, String[] exclude, Boolean overwrite)
[09:35:29]: [Step 1/3]    at DeployFileShare.Program.Deploy(String num, String source)
[09:35:29]: [Step 1/3]    at DeployFileShare.Program.Main(String[] args)
[09:35:29]: [Step 1/3] Process exited with code -532459699

I think I need to authenticate myself. I’ve come across this:

AppDomain.CurrentDomain.SetPrincipalPolicy(PrincipalPolicy.WindowsPrincipal);
WindowsIdentity idnt = new WindowsIdentity(username, password);
WindowsImpersonationContext context = idnt.Impersonate();

I’ve also tried:

AppDomain.CreateDomain("192.168.0.76").SetPrincipalPolicy(PrincipalPolicy.WindowsPrincipal);
WindowsIdentity idnt = new WindowsIdentity("user", "pass");
WindowsImpersonationContext context = idnt.Impersonate();

I am not sure how to use it. When I run the application I get:

C:\Users\Administrator>DeployFileShare 1 R:\BuildOutput\_PublishedWebsites\Web 2
1
Deploy Started Web, version 21
-- Deploy Prepared
-- Deploying to 1

Unhandled Exception: System.Security.SecurityException: There are currently no l
ogon servers available to service the logon request.

   at System.Security.Principal.WindowsIdentity.KerbS4ULogon(String upn)
   at System.Security.Principal.WindowsIdentity..ctor(String sUserPrincipalName,
 String type)
   at DeployFileShare.Program.Authenticate(String server)
   at DeployFileShare.Program.Deploy(String num, String source)
   at DeployFileShare.Program.Main(String[] args)
The Zone of the assembly that failed was:
MyComputer

Here is the basic code:

static void Main()
{
Copy();
}
static void Copy()
{
AppDomain.CreateDomain(GetServerInfo(server, "server")).SetPrincipalPolicy(PrincipalPolicy.WindowsPrincipal);
            WindowsIdentity idnt = new WindowsIdentity(GetServerInfo(server, "user"), GetServerInfo(server, "pass"));
            WindowsImpersonationContext context = idnt.Impersonate();
string source = "C:\\someDir";
string dest = "\\192.168.0.76\shareFolder"
string[] sourceFiles = Directory.GetFiles(source, "*", SearchOption.AllDirectories);
            foreach (string file in sourceFiles)
            {
                string local = file.Replace(source, "");
                if (exclude.Contains(local))
                    continue;
                if (!Directory.Exists(Path.GetDirectoryName(dest + "\\" + local)))
                    Directory.CreateDirectory(Path.GetDirectoryName(dest + "\\" + local));
                File.Copy(file, dest + "\\" + local, overwrite);
                Console.WriteLine("-- -- [copied] {0} -> {1}", file, dest + "\\" + local);
            }
}

The code copy system in the for loop works, I’ve tested it on my local system.

If anyone knows how I should use WindowsIdentity and WindowsIdentity to get this to work please enlighten me. I’ve been looking around and window’s documentation doesn’t help much.

Basically how can I copy to a remote directory being shared by logging into the system?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:46:27+00:00Added an answer on May 26, 2026 at 9:46 pm

    VB but easily translated to C#. Do this before your copy:

    Private Sub Open_Remote_Connection(ByVal strComputer As String, ByVal strUserName As String, ByVal strPassword As String)
        Dim ProcessStartInfo As New System.Diagnostics.ProcessStartInfo
        ProcessStartInfo.FileName = "net"
        ProcessStartInfo.Arguments = "use \\" & strComputer & "\c$ /USER:" & strUsername & " " & strPassword
        ProcessStartInfo.WindowStyle = ProcessWindowStyle.Hidden
        System.Diagnostics.Process.Start(ProcessStartInfo)
        System.Threading.Thread.Sleep(2000)
    End Sub
    
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