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Home/ Questions/Q 6182469
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:12:16+00:00 2026-05-24T01:12:16+00:00

I am building a project using the Play framework and I am having trouble

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I am building a project using the Play framework and I am having trouble getting my head around JPA @OneToOne relationships.

I currently have two classes:

User Object

@Entity
@Table( name="users" )
public class Users extends Model {

    @OneToOne( mappedBy="userId", fetch=FetchType.LAZY, cascade = CascadeType.ALL )
    @ForeignKey( name="userId", inverseName="userId" )
    UserSettings userSettings;
    public userId;
    public userName;
}

UserSettings

@Entity
@Table( name="user_settings" )
public class UserSettings extends Model {

    @OneToOne( cascade = CascadeType.ALL,targetEntity=User.class )
    public String userId;
    public String xml;

    public UserSettings( String userId ){
        this.userId = userId;
    }
}

The idea is that I am trying to set the userId field within User as a foreign key within UserSettings. I have tried a few different ways to achieve this and my code always throws an error. The most common error I recveive is:
Referenced property not a (One|Many)ToOne.

However, When I try to set the userId in UserSettings using the code above, I receive the following exception:

A javax.persistence.PersistenceException has been caught, org.hibernate.PropertyAccessException: could not get a field value by reflection getter of reader.User.id

Can anybody help explain how I can achieve my desired goal?

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:12:17+00:00Added an answer on May 24, 2026 at 1:12 am

    Read section 5.2 of the hibernate reference about the difference between entities and values. You’re trying to map a String as an entity. Only entities can be a (One|Many)ToOne, as the error is telling you. I.e., instead of String userId, you should be using User user, and instead of mappedBy="userId", mappedBy="user".

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