Question

I am building an app with SBT (0.11.0) using a Scala build definition like so:

object MyAppBuild extends Build {

  import Dependencies._

  lazy val basicSettings = Seq[Setting[_]](
    organization  := "com.my",
    version       := "0.1",
    description   := "Blah",
    scalaVersion  := "2.9.1",
    scalacOptions := Seq("-deprecation", "-encoding", "utf8"),
    resolvers     ++= Dependencies.resolutionRepos
  )

  lazy val myAppProject = Project("my-app-name", file("."))
    .settings(basicSettings: _*)
    [...]

I’m packaging a .jar at the end of the process.

My question is a simple one: is there a way of accessing the application’s name (“my-app-name”) and version (“0.1”) programmatically from my Scala code? I don’t want to repeat them in two places if I can help it.

Any guidance greatly appreciated!

Answer 1

sbt-buildinfo

I just wrote sbt-buildinfo.
After installing the plugin:

lazy val root = (project in file(".")).
  enablePlugins(BuildInfoPlugin).
  settings(
    buildInfoKeys := Seq[BuildInfoKey](name, version, scalaVersion, sbtVersion),
    buildInfoPackage := "foo"
  )

Edit: The above snippet has been updated to reflect more recent version of sbt-buildinfo.

It generates foo.BuildInfo object with any setting you want by customizing buildInfoKeys.

Ad-hoc approach

I’ve been meaning to make a plugin for this, (I wrote it) but here’s a quick script to generate a file:

sourceGenerators in Compile <+= (sourceManaged in Compile, version, name) map { (d, v, n) =>
  val file = d / "info.scala"
  IO.write(file, """package foo
    |object Info {
    |  val version = "%s"
    |  val name = "%s"
    |}
    |""".stripMargin.format(v, n))
  Seq(file)
}

You can get your version as foo.Info.version.