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I am calling
handler.postDelayed(runnable, time);
handler.post(runnable2);
Will the second runnable not get handled until the first message in the queue does, after “time” has passed?
No. The second runnable will be posted immediately and would execute before the first — depending on the
timeparameter in the first, anyway. If you post the first with a negligible delay fortimeit’s possible it could execute first. I don’t believe there’s any guarantee in place that it wouldn’t.