Question

I am coding facebook kind request page for a project. I am stuck with grouping requests in all requests printed page.

my sql as

SQL = "SELECT R.REQUESTID, R.BYID, R.TOID, R.TYPE, R.DATEENTERED, M.MEMBERID, M.FIRSTNAME, M.LASTNAME"
SQL = SQL & " FROM REQUESTS R, MEMBERS M"
SQL = SQL & " WHERE R.ACTIVE = 1 AND R.TOID = "& Session("MEMBERID") &" AND R.BYID = M.MEMBERID"
SQL = SQL & " GROUP BY R.REQUESTID, R.BYID, R.TOID, R.TYPE, R.DATEENTERED, M.MEMBERID, M.FIRSTNAME, M.LASTNAME"
SQL = SQL & " ORDER BY R.DATEENTERED DESC"

Returns me results as
Friend
Edie
Friend
Frank
Group
George

But I need it as

Friend
Edie
Frank
Group
George

Answer 1

if there is more than one REQUESTS for one of the MEMBERS you are after, you will get duplicates.

look at this:

SELECT --select all columns required, can produce duplicates
    R.REQUESTID, R.BYID, R.TOID, R.TYPE, R.DATEENTERED, M.MEMBERID, M.FIRSTNAME, M.LASTNAME
    FROM REQUESTS            R
        INNER JOIN MEMBERS   M ON R.BYID = M.MEMBERID
    WHERE M.MEMBERID IN (SELECT --get distinct list of members to display
                             M.MEMBERID
                             FROM REQUESTS            R
                                 INNER JOIN MEMBERS   M ON R.BYID = M.MEMBERID
                             WHERE  R.ACTIVE = 1 AND R.TOID = ___MEMBERID__
                             GROUP BY M.MEMBERID
                        )
    ORDER BY R.DATEENTERED DESC