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Home/ Questions/Q 7718535
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T03:11:23+00:00 2026-06-01T03:11:23+00:00

I am coding for my Applictation , i came across a requirement , where

  • 0

I am coding for my Applictation , i came across a requirement , where i needed to convert a String to char array I

String str_a = "Testing";

char c[] = str_a.toCharArray(); 

for (char d : c) {
    System.out.println(d);
}

As i did not initialize the char c[]

My question is why it doesn’t throw a NullPointerException, typically this should be done this way

char[] char_array = new char[str_a.length()];

char_array = str_a.toCharArray();       

for (char d : c) {
    System.out.println(d);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T03:11:24+00:00Added an answer on June 1, 2026 at 3:11 am

    The source code of toCharArray():

    /**
     * Converts this string to a new character array.
     *
     * @return  a newly allocated character array whose length is the length
     *          of this string and whose contents are initialized to contain
     *          the character sequence represented by this string.
     */
    public char[] toCharArray() {
        char result[] = new char[count]; // <-- Here is the initialization :)
        getChars(0, count, result, 0);
        return result;
    }
    
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