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Home/ Questions/Q 8738341
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T10:42:46+00:00 2026-06-13T10:42:46+00:00

I am coding MVC. In my controller i am listening to the action and

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I am coding MVC. In my controller i am listening to the action and if the user clicks a “SHOW-LIST” button i am making an instance of my view class which extends from JFrame and therein the view class i create a new JFrame. My problem is that if i click on SHOW-LIST button multiple times, i have the frame opened multiple time. Can somebody please tell me how can i do so so that once a new frame is about to open the old frame closes..

Controller

public void actionPerformed(ActionEvent event) {
  String viewAction = event.getActionCommand();
  ...
    if (viewAction.equals("SHOW-LIST")) {
      showListUI = new ShowListDialogUI(displayedCustomerList);
    }
}

View

class ShowListDialogUI extends JFrame{
  public ShowListDialogUI (List<Customer> customerList) {
    ..
    // I am drawing it here
    ..
  }
}
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  1. Editorial Team
    Editorial Team
    2026-06-13T10:42:47+00:00Added an answer on June 13, 2026 at 10:42 am

    Can somebody please tell me how can i do so so that once a new frame
    is about to open the old frame closes..

    • use CardLayout, then there no reason to playing with Top-Level Containers, put there required number of JPanels, then just to switch betweens JPanel views

    • as @trashgod notified, really not good idea, way

    • otherwise have to clean-up (remove all contents) uselless container, because Top-Level Containers never will be GC’ed

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