Question

I am coming across a strange thing. I have a number in binary in the form of string particularly “01001100”. But I am getting the exception mentioned above by executing the following code.

String s = "01001100";
byte b = Byte.parseByte(s);

But why is it happening? Whereas in a byte we can store max no. upto 127 and min. upto -128.
And the decimal equivalent of the above number is 76 which is perfectly in the range.

The particular exception I am getting is as:

java.lang.NumberFormatException:Value out of range. value:01001100 radix:10

Is there any way to get rid of it. Yes and it is compulsory for me to use byte only as I am extracting the data stored in the image byte by byte only.
Thank you.

Answer 1

The key is at the end of the exception string: radix:10. You are converting the decimal value 1,001,100 to a byte, and it does not fit. Try this:

String s = "01001100";
byte b = Byte.parseByte(s, 2);