Question

I am comparing 2 xml files using xml diff dll.
I am unable to get the node name and the old value of the node like for example
file 1 :

File 1

<LastNameInfo>
    <LNameNum>1</LNameNum>
</LastNameInfo>

File 2 :

<LastNameInfo>
    <LNameNum> 5</LNameNum>
</LastNameInfo>

I even need to out put the node name in this example LnameNum and also the old value 1 can some one help??

Answer 1

so the way the XMLDiff ‘diffgram’ defines the differences is not based on ‘name’ but on node order, it enumerates them from the top down.

Take a look at the MSDN for more details

You can use the diffpatch tool to apply a diffgram to a particular XML, but also it does not mention explicitly the ‘old’ value in the diffgram. Its either a change to ‘newvalue’, or a remove node x, without specifying the contents.

It has the ability to output a HTML view that shows the old and new side by side with color highlighting- but if you are interested in doing something like producing a file that looks like this:

<LastNameInfo>
  <LNameNum>
    <old>1</old>
    <new>5</new>
  </LNameNum>
</LastNameInfo>

Or even just some console output like:

Node Name: LNameNum
Changed From: 1 To: 5

You are going to need to parse the XML Diffgram yourself along with your own file and basically find out that

 <xd:node match="1">
       <xd:change match="1"/>5</xd:change>
 </xd:node>

Is referring to the node named LNameNum