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Home/ Questions/Q 894167
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T14:20:21+00:00 2026-05-15T14:20:21+00:00

I am comparing two binary arrays. I have an array where values can either

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I am comparing two binary arrays. I have an array where values can either be one or zero, one if the values are the same and zero if they are not. Please note I am doing other stuff beyond checking, so we don’t need to get into vectorization or the nature of the code.

What is more efficient, using a numerical array or a logical array in MATLAB?

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  1. Editorial Team
    Editorial Team
    2026-05-15T14:20:22+00:00Added an answer on May 15, 2026 at 2:20 pm

    Logical values take up fewer bytes than most numeric values, which is a plus if you’re dealing with very large arrays. You can also use logical arrays to do logical indexing. For example:

    >> valArray = 1:5;                   %# Array of values
    >> numIndex = [0 1 1 0 1];           %# Numeric array of ones and zeroes
    >> binIndex = logical([0 1 1 0 1]);  %# Logical array of ones and zeroes
    >> whos
      Name          Size            Bytes  Class      Attributes
    
      binIndex      1x5                 5  logical       %# 1/8 the number of bytes
      numIndex      1x5                40  double        %#   as a double array
      valArray      1x5                40  double               
    
    >> b = valArray(binIndex)            %# Logical indexing
    
    b =
    
         2     3     5
    
    >> b = valArray(find(numIndex))      %# You have to use the FIND function to
                                         %#   find the indices of the non-zero
    b =                                  %#   values in numIndex
    
         2     3     5
    

    One note: If you will be dealing with arrays of zeroes and ones that are very sparse (i.e. very few ones), it may be best to use an array of numeric indices such as you would get from the FIND function.Take the following example:

    >> binIndex = false(1,10000);      %# A 1-by-10000 logical array
    >> binIndex([2 100 1003]) = true;  %# Set 3 values to true
    >> numIndex = find(binIndex)       %# Find the indices of the non-zero values
    
    numIndex =
    
               2         100        1003
    
    >> whos
      Name          Size               Bytes  Class      Attributes
    
      binIndex      1x10000            10000  logical       %# 10000 bytes versus
      numIndex      1x3                   24  double        %#   many fewer bytes
                                                            %#   for a shorter array
    
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