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Home/ Questions/Q 7677171
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T17:21:45+00:00 2026-05-31T17:21:45+00:00

I am compiling baremetal software (no OS) for the Beagleboard (ARM Cortex A8) with

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I am compiling baremetal software (no OS) for the Beagleboard (ARM Cortex A8) with Codesourcerys GCC arm EABI compiler. Now this compiles to a binary or image file that I can load up with the U-Boot bootloader.

The question is, Can I load hexdata into memory dynamically in runtime (So that I can load other image files into memory)? I can use gcc objcopy to generate a hexdump of the software. Could I use this information and load it into the appropriate address? Would all the addresses of the .text .data .bss sections be loaded correctly as stated in the linker script?

The hexdata output generated by

$(OBJCOPY) build/$(EXE).elf -O binary build/$(EXE).bin
od -t x4 build/$(EXE).bin > build/$(EXE).bin.hex

look like this:

0000000 e321f0d3 e3a00000 e59f1078 e59f2078
0000020 e4810004 e1510002 3afffffc e59f006c
0000040 e3c0001f e321f0d2 e1a0d000 e2400a01
0000060 e321f0d1 e1a0d000 e2400a01 e321f0d7

… and so on.

Is it as simple as to just load 20 bytes for each line into the desired memory address and everything would work by just branching the PC into the correct address? Did I forget something?

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  1. Editorial Team
    Editorial Team
    2026-05-31T17:21:46+00:00Added an answer on May 31, 2026 at 5:21 pm

    when you use -O binary you pretty much give up your .text, .data. .bss control. For example if you have one word 0x12345678 at address 0x10000000 call that .text, and one word of .data at 0x20000000, 0xAABBCCDD, and you use -O binary you will get a 0x10000004 byte length file which starts with the 0x12345678 and ends with 0xAABBCCDD and has 0x0FFFFFFC bytes of zeros. try to dump that into a chip and you might wipe out your bootloader (uboot, etc) or trash a bunch of registers, etc. not to mention dealing with potentially huge files and an eternity to transfer to the board depending on how you intend to do that.

    What you can do which is typical with rom based bootloaders, is if using gcc tools

    MEMORY
    {
       bob : ORIGIN = 0x10000000, LENGTH = 16K
       ted : ORIGIN = 0x20000000, LENGTH = 16K
    }
    
    SECTIONS
    {
       .text : { *(.text*) } > bob
       .bss  : { *(.bss*) } > ted AT > bob
       .data : { *(.data*) } > ted AT > bob
    }
    

    The code (.text) will be linked as if the .bss and .data are at their proper places in memory , 0x20000000, but the bytes are loaded by the executable (an elf loader or -O binary, etc) tacked onto the end of .text. Normally you use more linkerscript magic to determine where the linker did this. On boot, your .text code should first zero the .bss and copy the .data from the .text space to the .data space and then you can run normally.

    uboot can probably handle formats other than .bin yes? It is also quite easy to write an elf tool that extracts the different parts of binaries and makes your own .bins, not using objcopy. It is also quite easy to write code that never relies on .bss being zero nor has a .data. solving all of these problems.

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