Question

I am completely new to C and need help with this badly.
Im reading a file with fopen(), then obtaining the contents of it using fgetc(). What I want to know is how I can access the line fgetc() returns so if I can put the 4th – 8th characters into a char array. Below is an example I found online but am having a hard time parsing the data returns, I still don’t have a firm understanding of C and don’t get how an int can be used to store a line of characters.

    FILE *fr;
fr = fopen("elapsed.txt", "r");
int n = fgetc(fr);
    while(n!= EOF){
        printf("%c", n);
        n = fgetc(fr);
    }   printf("\n");

Answer 1

You’re not retrieving a line with fgetc. You are retrieving one character at a time from the file. That sample keeps retrieving characters until the EOF character is encountred (end of file). Look at this description of fgetc.

http://www.cplusplus.com/reference/clibrary/cstdio/fgetc/

On each iteration of the while loop, fgetc will retrieve a single character and place it into the variable “n”. Something that can help you with “characters” in C is to just think of it as one byte, instead of an actual character. What you’re not understanding here is that an int is 4 bytes and the character is 1 byte, but both can store the same bit pattern for the same ASCII character. The only different is the size of the variable internally.

The sample you have above shows a printf with “%c”, which means to take the value in “n” and treat it like an ASCII character.

http://www.cplusplus.com/reference/clibrary/cstdio/printf/

You can use a counter in the while loop to keep track of your position to find the 4th and 8th value from the file. You should also think about what happens if the input file is smaller than your maximum size.

Hope that helps.