I am completely new to DOM Documents, basically what I am trying to do, is to load a RSS feed in and select only one node, and then save it to a XML file.
Here is the XML I am loading from a web feed:
<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0">
<channel>
<title>Markets</title>
<description/>
<link>http://www.website.com</link>
<language>en-us</language>
<copyright>XML Output Copyright</copyright>
<ttl>15</ttl>
<pubDate>Tue, 16 Nov 2010 09:38:00 +0000</pubDate>
<webMaster>admin@website.com</webMaster>
<image>
<title>title</title>
<url>http://www.website.com/images/xmllogo.gif</url>
<link>http://www.website.com</link>
<width>144</width>
<height>16</height>
</image>
<item>
<title>title</title>
<description>the description goes here
</description>
<enclosure url="http://www.website.com/images/image.png" type="image/png"/>
</item>
</channel>
</rss>
Here is my lame attempt at getting the <description> node and saving it to feed.xml:
<?php
$feed = new DOMDocument();
$feed->load('http://www.website.com/directory/directory/cz.c');
$nodeValue = $feed->getElementsByTagName('description')->item(0)->nodeValue;
$feed->save("feed.xml");
?>
So basically I need to get the description tag, and save it as a XML file.
Any help would be appreciated, thanx in advance!
Almost correct. To get the “outerXml” of a node, you can pass the node to
saveXml()Saving with
file_put_contentswill not include an XML prolog. Note that in your example, the first description element is empty, so the file will contain<description/>.If you want to extract the node as standalone XML Document, you have to instantiate a new
DOMDocumentand import theDOMNodeand then usesave().