Question

I am completely newbie in C.
I am trying to do simple C function that will split string (char array).

The following code doesn’t work properly because I don’t know how to terminate char array in the array. There are to char pointers passed in function. One containing original constant char array to be split and other pointer is multidimensional array that will store each split part in separate char array.

Doing the function I encountered obviously lots of hustle, mainly due to my lack of C experience.

I think what I cannot achieve in this function is terminating individual array with ‘\0’.
Here is the code:

void splitNameCode(char *code, char *output);

void splitNameCode(char *code, char *output){

    int     OS = 0; //output string number
    int     loop;
    size_t  s = 1;

    for (loop = 0; code[loop]; loop++){
        if (code[loop] == ':'){ 
            output[OS] = '\0'; // I want to terminate each array in the array
            OS ++;
        }else {
            if (!output[OS]) {
                strncpy(&output[OS], &code[loop], s);
            }else {
                strncat(&output[OS], &code[loop], s);
            }
        }
    }
}

int main (int argc, const char * argv[]) {

    char output[3][15];
    char str[] = "andy:james:john:amy";
    splitNameCode(str, *output);

    for (int loop = 0; loop<4; loop++) {
        printf("%s\n", output[loop]);
    }

    return 0;
}

Answer 1

Here is a working program for you. Let me know if you need any explanation.

#include <stdlib.h>
#include <string.h>
#include <stdio.h>

void splitNameCode(char *code, char **output) {
    int i = 0;
    char* token = strtok(code, ":");
    while (token != NULL) {
        output[i++] = token;
        token = strtok(NULL, ":");
    }
}

int main (int argc, const char *argv[]) {
    char* output[4];
    char input[] = "andy:james:john:amy";
    splitNameCode(input, output);
    for (int i = 0; i < 4; i++) {
        printf("%s\n", output[i]);
    }
    return 0;
}