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Home/ Questions/Q 6953957
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:32:39+00:00 2026-05-27T14:32:39+00:00

I am completely stumped on what appears to be a trivial problem. I have

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I am completely stumped on what appears to be a trivial problem.

I have this function:

function findCategoryNameInTree($id, $tree) {
    foreach($tree as $branch) {
        if ($branch['category_id'] == $id) {
             echo $branch['name'];//works
             print_r($branch['name']);//works
             //return($branch['name']); //returns nothing
             return $branch['name'];//fix this line per feedback still no return value
        } else {
            if(count($branch['children']) > 0) {
                findCategoryNameInTree($id,$branch['children']);
            }
        }

    }
}

I can’t figure out for the life of me why it’s not returning anything.

Please help!

Edit
Here’s how I call my function

//what I really want to do
$primgenre = findCategoryNameInTree($cat_id,$category_tree['children']);

//but this doesnt work either
echo $primgenre;

//nor this
print_r($pringenre);
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  1. Editorial Team
    Editorial Team
    2026-05-27T14:32:40+00:00Added an answer on May 27, 2026 at 2:32 pm

    You forget to return for this :-

    findCategoryNameInTree($id,$branch['children']);
    

    Change :-

    return findCategoryNameInTree($id,$branch['children']);
    
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