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Home/ Questions/Q 948191
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:12:12+00:00 2026-05-15T23:12:12+00:00

I am confused by this behaviour of Python(2.6.5), can someone shed light on why

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I am confused by this behaviour of Python(2.6.5), can someone shed light on why this happens?

class A(): 
    mylist=[]  


class B(A):
    j=0
    def addToList(self):
        self.mylist.append(1)


b1 = B()
print len(b1.mylist)  # prints 0 , as A.mylist is empty
b1.addToList()
print len(b1.mylist)  # prints 1 , as we have added to A.mylist via addToList()

b2 = B()
print len(b2.mylist)  # prints 1 !!! Why ?????
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  1. Editorial Team
    Editorial Team
    2026-05-15T23:12:12+00:00Added an answer on May 15, 2026 at 11:12 pm

    You need to do:

    class A: 
         def __init__(self):
             self.mylist=[] 
    

    That way self.mylist is an instance variable. If you define it outside of a method it is a class variable and so shared between all instances.

    In B if you define a constructor you’ll have to explicitly call A’s constructor:

    class B(A):
        def __init__(self):
            A.__init__(self)
    

    This is explained (not very clearly) in the Python tutorial.

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