Question

I am confused with this program.

#include <stdio.h>

int main(void)
{
    char* ptr="MET ADSD";

    *ptr++;
    printf("%c\n", ptr);

    ptr++;
    printf("%c\n", ptr);
}

Here’s the output.

ET ADSD
T ADSD

My question is how does the pointer display the rest of the characters?

Answer 1

You are passing a wrong combination of parameters to printf: the %c format specification requires a char parameter, not a char*. So the result is undefined – in your case printf seems to print the whole char array, but this is just by pure chance. Use either

printf("%c\n", *ptr);

or

printf("%s\n", ptr);